F(x)=-16x^2+50x+9

Solution for F(x)=-16x^2+50x+9 equation:

(F)=-16F^2+50F+9

We move all terms to the left:

(F)-(-16F^2+50F+9)=0

We get rid of parentheses

16F^2-50F+F-9=0

We add all the numbers together, and all the variables

16F^2-49F-9=0

a = 16; b = -49; c = -9;
Δ = b2-4ac
Δ = -492-4·16·(-9)
Δ = 2977
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{2977}}{2*16}=\frac{49-\sqrt{2977}}{32}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{2977}}{2*16}=\frac{49+\sqrt{2977}}{32}
$